Prediction
If K doubles and T halves, what changes in a unit-step response?
Sketch your prediction: mark the final value, the value at one time constant, and the initial slope.
One curve, two independent meanings
For the first-order model , initially at rest, a unit step produces
The gain sets the final value. The time constant stretches the horizontal axis. At , every PT1 response has completed the same fraction of its journey:
Concept check
A unit-step response settles at 4.0. What output marks one time constant?
Reactive experiment: reshape the response
This plot is already present in the built HTML. When Python activates, both sliders update it without rerunning any cells manually.
Worked example
A heater has and . A step eventually raises the temperature by . After , the rise is .
Derivation
Solve the homogeneous and forced parts
The homogeneous equation T ẏ + y = 0 gives yₕ = C exp(-t/T). A constant unit input has the particular solution yₚ = K. Applying y(0)=0 gives C=-K, so y=K(1-exp(-t/T)).
Unofficial TUM ACE exam prep
Use the tangent and 63% constructions carefully
State which construction you use and measure changes relative to the pre-step baseline. A delayed first-order response needs a separate delay parameter; forcing it into T biases the model.
Python exercise: implement the analytical response
Complete the function. All execution stays in your browser. Syntax and runtime errors appear below the editor and cannot break the surrounding lesson.
Summary
- sets the response scale; sets the time scale.
- At , a PT1 response reaches 63.2% of its total change.
- The analytical formula, numerical plot, and physical interpretation must agree.
Retrieve it later
Derive the 63.2% rule and explain what would happen to the curve if K doubles while T halves.
Answer from memory tomorrow, then return to check your reasoning.